There is construction on the roads B - N which prevent any cars from crossing. Using any combination you wish without using the same means twice, what is the fastest time it would take you to travel from H to A and then to O?;
CAR = 2 MIN
BIKE = 2 MIN 20 SEC
FOOT = 3 MIN 20 SEC
I keep getting 20 min 20 sec? The actual answer is 20 min flat? Am I wrong???
Any help appreciated
When I come up to 20min flat, it pretty much takes away the rule of not using the same mean twice.
What I did to come to 20 min is:
Bike H - A = 9min 20 sec
Drive A - M = 6 min
Bike M - o = 4 min 40 sec
Total: 20 min ( but using bike twice ) :?
Yea. But when you look at the solution it shows that they used the Car once and the Bike the rest of the way. Might be an error in the answer. Unless I'm doing it worng?
car h-d-c-b =6 min
bike b-a-e-i-m-n-o=14 min
equals 20 minutes flat
Originally Posted by flim flam
Car:
H-D-C-B = 3 STEPS x 2 MIN = 6 MIN
Bike:
B-A-E-I-M-N-O = 6 STEPS x 2 MIN 20 SEC = 13.20
TOTAL = 13.20 + 6 = 19.20???
How is it 20min?
Am i doing something wrong????
Thanks!!
You have multiplied incorrectly....
6x2min 20sec= 14min
you have to remeber that there are 60sec in a min.
6x2min=12min
6x20sec=120sec=2min
12min+2min=14min.
dont do any multiplying, try to add it
Car:
H-D-C-B = 3 STEPS x 2 MIN = 6 MIN
Bike:
B-A-E-I-M-N-O = 6 STEPS x 2 MIN 20 SEC = 13.20
TOTAL = 13.20 + 6 = 19.20???
How is it 20min?
Am i doing something wrong????
Thanks!!
Got it. Thanks fellas!!!
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